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To Find | Direct Current | Alternating Current | ||
Single Phase | Two-Phase* Four-Wire | Three Phase | ||
Amperes when Horsepower is known | HP x 746 | HP x 746 | HP x 746 | HP x 746 |
E x EFF | E x EFF x PF x 2 | 2 x E x EFF x PF | E x EFF x PF x 1.73 | |
Amperes when Kilowatts are known | KW x 1000 | KW x 1000 | KW x 1000 | KW x 1000 |
E | E x PF | 2 x E x PF | E x PF x 1.73 | |
Amperes when "KVA" is known | KVA x 1000 | KVA x 1000 | KVA x 1000 | |
E | E x 1.73 | |||
Kilowatts | E x I | E x I x PF | I x E x 2 x PF | E x I x 1.73 x PF |
1000 | 1000 | 1000 | 1000 | |
Kilovolt-Amperes "KVA" | I x E | I x E x 2 | E x I x 1.73 | |
1000 | 1000 | 1000 | ||
Horsepower (Output) | E x I x EFF | E x I x EFF x PF | I x E x 2 x EFF x PF | E x I x EFF x PF x 1.73 |
746 | 746 | 746 | 746 | |
E = Voltage I = Amps PF = Power Factor EFF = Efficiency HP = Horsepower |
Note: Direct current formulas do not use (PF, 2, or 1.73)
Single phase formulas do not use (2 or 1.73)
Two phase-four wire formulas do not use (1.73)
Three phase formulas do not use (2)
* For three-wire, two phase circuits the current in the common conductor is 1.41 times that in either of the other two conductors.
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